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The Art of Problem Solving
a few questions:1. given a measurable set E (in R) with finite (lebesgue) measure, and any 0 < a < 1, there exists a subset A of E such that m(A) = am(E). i know this is true for a = 1/2, but how about all a in (0, 1)?2. this one i...
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The Art of Problem Solving
Let M and N be complex measures on R^k. Is it true that |MxN| = |M|x|N|? It seems to me that this should be true, since the two measures above aggree on elementary sets (finite disjoint unions of measurable rectangles). They should,...
The Art of Problem Solving
Let E be a subset of the reals. If E is measurable, then for all e > 0, there exists a closed set F contained in E such that m(E-F) < e. Now, I've already proved that if E is measurable, then for all e > 0, there is an open set O co...
The Art of Problem Solving
the only open set of (lebesgue) measure zero is the empty set.i suspect true, but real analysis is full of annoying counter-intuitive counterexamples.thanks!
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